rubik's cube fails

not all world speedcuber can solve the cube, so i upload this video

how to solve rubik's cube

 to solve the rubik's cube is very easy, every one can solve the rubik's cube if they learning and practice

The Rubik's cube is the best selling toy in the U.S.
some may think it is impossible to solve, even  Erno Rubik didn't think there was a combination to
there are 43,000,000,000,000,000,000 (that is 43 quintillion) possible combinations.
So how can you solve the cube without memorizing 43 quintillion different combinations?
there are things called algorithms that are based on mathematical equations that get pieces to places without messing up the whole cube.
   Some of you may be wondering why i wanted to learn to solve the Rubik's cube, well I am very big into math and I am Very good at memorizing things in fact I have an IQ of 120 but you don't need a high iq to learn how to solve the Rubik's cube. I learn this method last Christmas when I was bored on Christmas break and wanted something to do. It only took me a week to learn to solve it, but it wasn't like I was doing it for a week straight 24 hours a day, in fact i probably spent an hour a day max that's 7 hours max it took me to solve the Rubik's cube. So in this tutorial i will show you a beginners method that I used on how to solve the Rubik's cube and maby later i might teach you an advance method on how to solve it, but you will need to know how to solve it with the beginners method first before you move onto the advanced method.

What You Need
- A Rubik's cube
- an Attentive mindset

Step 1:

To get how to solve the Rubik's cube i will explain to you how this method solves it.
Most people think you solve the cube face by face but that is wrong you are supposed to solve one face then layer by layer.

the blue picture below shows the notation of moves that make up an algorithm

first things first you need to get the cross it doesn't matter what color it is as long as you have a cross where the colors on the sides match

Note: what I mean by the colors on the side matching is if you are solving the red faces cross the color of the edge piece should match up with it's side

Step 2:

Now you will need to get the rest of the first side

to get the white piece up to where it needs to be
the algorithm for it with the green side facing you is

R, Fi, Ri, F

the algorithm for the bottom picture is

F, D, Fi, Di, R, Fi, Ri, F


these are algorithms that I invented

Step 3:

Congratulations you have solved the first side  but that isn't very impressive so lets go on.
Now you need to flip the solved side so its on the bottom so you can get the edge pieces aligned also known as the second layer

you need to find the edge pieces that belong in the middle row

you need to find an edge piece and line it up with its color
if it has to the right the algorithm you need to use is
U, R, Ui, Ri, Ui, Fi, U, F

if it has to go to the left use this algorithm
Ui, Li, U, L, U, F, Ui, Fi,

now do that to all the edge pieces
you are 2/3rd's of the way done

Step 4:

Now you have the first 2 layers finished

you now need the top cross
keep doing this algorithm until the top cross is solved
F, U, R,  Ui, Ri, Fi
now you should have the top cross

to solve the top face of the Rubik's cube you will need to do this algorithm
until the top of you Rubik's cube looks like the  picture then turn the whole cube to the right and do the again. if the top of you cube is solved your good but if it isn't get turn it so it looks like the picture then turn it to the right then do the algorithm again
R, U, Ri, U, R, U, U, Ri
now all you need to do is get the 3rd layer done

Step 5:

Now you have the first 2 layers and the top  your so close

if you have a combination like the orange side  where there is only one one odd piece turn the top layer so it is on the back side then do this algorithm
Ri, F, Ri, B, B, R, Fi, Ri, B, B, R, R, Ui

Now your cube should look like the 2nd  and 3rd picture with 3 faces with only 1 piece off
go to the opposite face off the one fully solve face and if the odd piece has to go to the right  do this algorithm

F, F, Ui, L, Ri, F, F, Li, R, Ui, F, F

If it needs to go left do this algorithm

F, F, U, L, Ri, F, F, Li, R, U, F, F

Step 6: Finished

Congratulations You have now solved the Modern day mystery; The Rubik's Cube
but if all this went right over your head try checking out this link it does a very good job explaining how to solve it          http://www.rubiks.com/solving-center/3x3_guide/

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Bottom of Form

cara menyelesaikan rubik 3x3 untuk pemula

belajar rubik 3x3 bagi pemula

     ada yang ingin belajar rubik...?? menyelesaikan rubik...??..ok langsung saja ada beberapa tahapan untuk menyelasaikan rubik mulai dari perkenalan bagian-bagian rubik sampai cara penyelesaianya.

1.tahap perkenalan
     tahap ini adalah tahap yang harus dikuasa terlebih dahulu untuk menyelesaikan rubik, dan ini hukumnya sunnah karena tahap ini untuk mempercepat dan mempermudah menyelesaikan rubik.

2.tahap muter rubik/pengenalan notasi
     muter rubik ini hukumnya adalah wajib karena tahap ini menentukan berhasil tidaknya suatu rumus karena jika rumusnya gagal maka otomatis rubik tidak akan terselesaikan..hhee.
     prinsipnya adalah F(front=depan) berati yang diputer bagian belakang searah jarum jam. prinsip tersebut juga berlaku pada semua sisi B(back=belakang), Down(under=bawah),  U(up=atas), R(right=kanan), dan L(left=kiri). agar lebih jelas lihat gambar dibawah ini.
catatan: jika terdapat tanda petik/aksen (‘) maka diputar  berlawanan arah jarum jam.

3.tahap membentuk cross
     tahap ini membentuk tanda cross disisi bawah, cara pertama buat seperti gambar dibawah ini.

catatan: pada kali ini saya menggunakan sisi kuning sebagai sisi bawah.

4.tahap menyelesaikan corner dengan benar

     tahap ini memang cukup lama bagi pemula untuk menyelesaikanya, tapi tenang jika anda cermat dan sabar pasti anda bisa menyelesaikannya.
jika terdapat gambar seperti ini.

Rumus: R, U, R'


Rumus: L', U', L


     jika tidak terdapat seperti gambar diatas jangan bingung kan ada aku,,hhee.


Rumus: R, U', R

Rumus: L', U, L

Rumus: R, U', R

5.tahap menyelesaikan layer ke-2

    tahap ini adalah tahap yang paling mudah dari semua tahap yang ada, prinsipnya adalah memindahkan edge sisi atas ke edge sisi samping, faham kan...?? faham donk.

Rumus: U, R, U', R', U', F', U, F

Rumus: U', L', U, L, U, F, U', F

     jika tidak juga menemukan gambar seperti diatas coba putar-putar sisi atas sampai ketemu, jika tidak ketemu juga berfikitrlah sedikit dan ingat prinsipnya.

6.tahap menyelesaikan sisi atas

     tahap ini memang menggunakan rumus yang sama berulang-ulang, jidi diharapkan sedit sabar menghadapi tahap ini.

 jika menemukan gambar seperti dibawah ini.

Rumus: F, R, U, R', U', F'

Rumus: R, U, R', U, R, 2U, R'

7.tahap final

      yeee,,,,akhirnya sudah sampai tahp final, ok langsung saja.

jika menemukan gambar serperti berikut.

Rumus: R, 2U, R', U', R, 2U, L', U, R', U', L

    kurasa anda sudah mengerti cara menyelesaikan rubik, maka yang satu ini saya akan membahas prinsipnya saja. prinsipnya adalah memindahkan edge dengan jalur memutar (kecuali edge belakang), lebih mudahnya perhatikan gambar berikut.

Rumus: 2F, (U/U'), L, R', 2F, L', R, (U,U')

catatan: pada gambar diatas jika edge yang mau dipindahkan berlawanan arah jarum jam maka (U/U') menggunakan U', jika searah jarum jam maka menggunakan U

pll algorithm

this algorithm for solve permutation in last step

Diagram	Algorithm	Name	Chance of Occurence	Difficulty to Learn	Comment
	x [(R' U R') D2] [(R U' R') D2] R2	A (a)	1/18	XXX	The algorithm has a little bit of a symmetry to it. I have a very weird way to memorize this algorithm tracking the two corners in UBR and UFR around the cube as I do it. But I know that many of my friends do it differently. Find what suits you best, it is not too hard or long.
	x' [(R U' R) D2] [(R' U R) D2] R2	A (b)	1/18	XX	This is the exact same type of motion you do in A(a). If you memorized it by motions instead of notation, you should be able to do this one without too many problems.
	[R U'] [R U] [R U] [R U'] R' U' R2	U (b)	1/18	X	Note how the algorithm is basically always R and then U' U U U' in that symmetrical order accompanying the R, and lastly R' and fix up rest by aligning pieces.
	R2 U [R U R' U'] (R' U') (R' U R')	U (a)	1/18	X	The way I remember it: R2 U, then the RUR'U' trigger, then the last two letters of the RUR'U' trigger, then do R' and fix up rest by aligning pieces and putting them to their right positions.
	M2 U M2 U2 M2 U M2	H	1/72	X	A very easy to remember algorithm. Note how the M2's always alternate, and in between you simply have just U, U2, U
	[R U R' U'] [R' F] [R2 U' R'] U' [R U R' F']	T	1/18	XX	I find it easy to learn this algorithm by tracking F2L pairs around the cube.RUR'U' takes out a pair. R'F hides it and takes the other pair out to the top layer. R2U'R' aligns this pair with the whites and hides that pair. Now all the pairs are hidden from the top layer. Now we do U' on the Top Layer. Finally RUR'F' takes the second pair out and aligns it with the whites again, and restores the First Two Layers.
	[R U R' F'] {[R U R' U'] [R' F] [R2 U' R'] U'}	J (b)	1/18	X	Notice that this is EXACTLY the same algorithm as the one above but the RUR'F' from the end was now moved to the beginning! So just do RUR'F' and then start doing the T permutation (above) until you see that the cube is solved!
	F R U' R' U' [R U R' F'] {[R U R' U'] [R' F R F']}	Y	1/18	XX	Again I find it helpful to see how F2L pairs move around for this algorithm. F brings an F2L pair to the top, RU'R' inserts that pair back to the middle. Now again as before, all F2L is again intact, but slightly messed up. Then U' is done as in T permutation, and then RUR'F' is AGAIN used to take that pair and insert it back where it was before. The result will leave you with an OLL, which after when you fix using the appropritate algorithm, you will be left with Ypermutation at the end. Note that the OLL is very easy: It takes one pair out to top layer, and inserts it back a different way (in particular, using R'FRF')
	[R' U2 R U2] [R' F] [R U R' U'] [R' F'] R2 U'	R (b)	1/18	XX	Again for this one I find it easiest to track an F2L pair. Remember the first part using just notation because it is easy. After R'F you have an F2L pair on the bottom. Then you do RUR'U' trigger. Next, R'F' reconnects that F2L pair and alligns it with the whites on top, and R2U' just finishes it all up.
	[L U2' L' U2'] [L F'] [L' U' L U] [L F] L2' U y2 [R U2 R' U2] [R B'] [R' U' R U] [R B] R2 U	R (a)	1/18	X	This is just the reflection of the above. You need to do the above, but using the left hand instead of the right hand. You will be able to mirror the R permutation to your left hand after about a weeks practice of doing it with your right hand. When it becomes a little bit of muscle memory for you it should be really easy to mirror the algorithm with the left hand. So if you can't do it right away, just wait a little more and get a little more comfortable with R(b). The second algorithm is an alternative that I sometime like to do because it involves the (faster) right hand instead.
	[R' U R' d'] [R' F'] [R2 U' R' U] [R' F R F]	V	1/18	XXXX	I don't really have a great way to memorize this and thats why I rated this as a hard algorithm. I kind of just did it until I had it in my muscle memory. Note how the R'FRF at the end is ALMOST the common R'FRF' trigger, but with F instead of F' at the end.
	[R' U2 R' d'] [R' F'] [R2 U' R' U] [R' F R U' F]	F	1/18	X	If you know V permutation, this one is REALLY easy. I highlighted the differences. There is simply one extra U, so instead of R' U R' in the beginning you have R' U U R' (or R' U2 R'), and then you have to undo that U at the end of the algorithm, so there is an extra U' that pops in from nowhere near the end of the algorithm.
	[R U R'] y' R2 u' R U' R' U R' u R2	G (d)	1/18	XX	RUR' takes out a pair. Then rotate the cube, and now the fun part starts. I highleted the R rotations so that you can see the pattern better. Notice in particular how the U turns are. It is u' U' U u. It has a very nice symmetry to it. The R's I remember as follows: Since in execution I perfrom the R2 as RR (in clockwise motion), I see them as R clockwise twice, and then R counterclockwise twice, and the final R2 is just to finish up the algorithm. You are welcome to come up with better memory techniques for this things. I know a couple of friends, each with different ways of remembering these G perms...
	[R' U' R] y R2 u R' U R U' R u' R2	G (b)	1/18	XX	This is similar. First take out the pair that is right under the aligned 2x1x1 block, as in G(d), and then rotate the cube, and do a similar pattern. See how there is a symmetry to the U's again? u U U' u'. When I execute, I do the first R2 as R' R', counterclockwise motion. So I think CCW, CCW, CW, CW, and final R2 just to fix it all up.
	R2 u' R U' R U R' u R2 [y R U' R']	G (c)	1/18	XXX	This is simply G(d) inverted. But I find it useless to remember it like that. This is like a completely new algorithm for me. Note the still distinct pattern to the U's. And also R's. Remember it as you wish. The last part yRU'R' just inserts an F2L pair once the first part is done.
	R2 u R' U R' U' R u' R2 [y' R' U R]	G (a)	1/18	XX	This is very similar to G(c). Everything just goes the other way :)
	M2 U M2 U M' U2 M2 U2 M' U2	Z	1/36	X	Similar to the H permutation, I find this easy to remember, and I saw some people executing it extremely quickly.
	[R' U L'] [U2 R U' R' U2] [R L U']	J (a)	1/18	XX	1st part is exactly as in N(b), below. But then you do U2RU'R'U2 which I find personally very easy to remember. The last part (RLU)just simply restores all yellows and I find it very easy to see it visually.
	x' (R U' R') D (R U R') D' (R U R') D (R U' R') D' x (R U' R') D (R U R') u2 (R' U R) D (R' U' R)	E	1/36	XX	This algorithm has a nice symmetry to it, as highlighted. Some people fund the second one faster to execute
	{(R' U L') U2 (R U' L)} {(R' U L') U2 (R U' L)} U'	N (b)	1/72	X	Note how the algorithm is made up of two IDENTICAL pieces (in squigly brackets). To memorize this, track the corner in UBR. As you do R'UL', it will travel along a U on the top layer of the cube. Then do U2, and then restore yellows by doing RU'L. Then repeat that whole thing again. I hate executing this algorithm. Its a good thing that it rarely ever comes up.
	{(L U' R) U2 (L' U R')} {(L U' R) U2 (L' U R')} U	N (a)	1/72	X	This is just the mirror of the algorithm above and should not be hard to learn.

CFOP method